Learn to Program 7
In this part of the Learn to Program tutorial series we will look at Dictionaries and one of the most confusing topics in programming being Recursive Functions. A Recursive Function is a function that calls for itself to execute. We’ll generate Factorials and Fibonacci numbers with recursive functions to help make them make more sense.
All of the commented code follows the video below.
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Code & Transcript
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# ---------- LEARN TO PROGRAM 7 ---------- # ---------- DICTIONARIES ---------- # While lists organize data based on sequential indexes # Dictionaries instead use key / value pairs. # A key / value pair could be # fName : "Derek" where fName is the key and "Derek" is # the value # Create a Dictionary about me derekDict = {"fName": "Derek", "lName": "Banas", "address": "123 Main St"} # Get a value with the key print("May name :", derekDict["fName"]) # Change a value with the key derekDict["address"] = "215 North St" # Dictionaries may not print out in the order created # since they are unordered print(derekDict) # Add a new key value derekDict['city'] = 'Pittsburgh' # Check if a key exists print("Is there a city :", "city" in derekDict) # Get the list of values print(derekDict.values()) # Get the list of keys print(derekDict.keys()) # Get the key and value with items() for k, v in derekDict.items(): print(k, v) # Get gets a value associated with a key or the default print(derekDict.get("mName", "Not Here")) # Delete a key value del derekDict["fName"] # Loop through the dictionary keys for i in derekDict: print(i) # Delete all entries derekDict.clear() # List for holding Dictionaries employees = [] # Input employee data fName, lName = input("Enter Employee Name : ").split() employees.append({'fName': fName, 'lName': lName}) print(employees) # ---------- PROBLEM : CREATE A CUSTOMER LIST ---------- # Create an array of customer dictionaries # Output should look like this ''' Enter Customer (Yes/No) : y Enter Customer Name : Derek Banas Enter Customer (Yes/No) : y Enter Customer Name : Sally Smith Enter Customer (Yes/No) : n Derek Banas Sally Smith ''' # Create customer array outside the for so it isn't local # to the while loop customers = [] while True: # Cut off the 1st letter to cover if the user # types a n or y createEntry = input("Enter Customer (Yes/No) : ") createEntry = createEntry[0].lower() if createEntry == "n": # Leave the while loop when n is entered break else: # Get the customer name by splitting at the space fName, lName = input("Enter Customer Name : ").split() # Add the dictionary to the array customers.append({'fName': fName, 'lName': lName}) # Print out customer list for cust in customers: print(cust['fName'], cust['lName']) # ---------- RECURSIVE FUNCTIONS ---------- # A function that refers to itself is a recursive function # Calculating factorials is commonly done with a recursive # function 3! = 3 * 2 * 1 def factorial(num): # Every recursive function must contain a condition # when it ceases to call itself if num <= 1: return 1 else: result = num * factorial(num - 1) return result print(factorial(4)) # 1st : result = 4 * factorial(3) = 4 * 6 = 24 # 2nd : result = 3 * factorial(2) = 3 * 2 = 6 # 3rd : result = 2 * factorial(1) = 2 * 1 = 2 # ---------- PROBLEM : CALCULATE FIBONACCI NUMBERS ---------- # To calculate Fibonacci numbers we sum the 2 previous # values to calculate the next item in the list like this # 1, 1, 2, 3, 5, 8 ... # The Fibonacci sequence is defined by: # Fn = Fn-1 + Fn-2 # Where F0 = 0 and F1 = 1 ''' Sample Run Though to Help print(fib(3)) # 1st : result = fib(2) + fib(1) : 2 + 1 # 2nd : result = (fib(1) + fib(0)) + (fib(0)) : 1 + 0 # 3rd : result = fib(2) + fib(1) print(fib(4)) # 1st : result = fib(3) + fib(2) : 3 + 2 # 2nd : result = (fib(2) + fib(1)) + (fib(1) + fib(0)) : 2 + 1 # 3rd : result = (fib(1) + fib(0)) + fib(0) : 1 + 0 ''' def fib(n): if n == 0: return 0 elif n == 1: return 1 else: result = fib(n-1) + fib(n-2) return result print(fib(3)) print(fib(4)) |
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